PROC main()
WriteF('Hello, World!')
ENDPROC
Ask the right questions to secure the right Amiga E talent among an increasingly shrinking pool of talent.
Amiga E, also known simply as E, is a programming language created by Wouter van Oortmerssen in the early 1990s for the Amiga personal computer. It is a procedural language with some object-oriented features, and its syntax is similar to that of C and Pascal. The language was designed to be efficient and powerful, with a strong emphasis on the production of compact, fast-executing code. Despite its niche status, Amiga E has a dedicated following and continues to be used in the Amiga community. Information about Amiga E can be found in various online resources, including the Amiga E website and the E Language Reference Manual.
The next 20 minutes of the interview should attempt to focus more specifically on the development questions used, and the level of depth and skill the engineer possesses.
Exception handling in Amiga E is implemented using the TRY, EXCEPT and ENDTRY keywords. The code that could potentially throw an exception is placed between TRY and EXCEPT, and the code to handle the exception is placed between EXCEPT and ENDTRY.
The MODULE keyword is used to create a module, which is a collection of related procedures and functions.
DEF is used to declare a variable, while CONST is used to declare a constant. Variables can be changed after they are declared, but constants cannot.
In Amiga E, a function is declared using the PROC keyword, followed by the function name and parameters in parentheses.
The basic data types in Amiga E are INT, CHAR, BOOL, ENUM, LIST, and OBJECT.
Enthusiasm can indicate that the candidate is genuinely interested in the role and the company. This can lead to higher job satisfaction and better performance.
Communication is key in any role. The candidate needs to be able to effectively communicate with team members, managers, and potentially clients.
Previous experience with software development projects can be a good indicator of the candidate's ability to manage tasks, meet deadlines, and work as part of a team.
While the focus is on Amiga E, having experience with other languages can be beneficial. It can show a broader understanding of programming concepts and versatility.
Software development often involves encountering and resolving unexpected issues. A good developer should be able to demonstrate their ability to troubleshoot and solve problems.
This is crucial as the role is specifically for an Amiga E developer. Their knowledge and understanding of the language will directly impact their ability to perform in the role.
The next 20 minutes of the interview should attempt to focus more specifically on the development questions used, and the level of depth and skill the engineer possesses.
Inheritance in Amiga E is implemented using the OBJECT keyword to create a new class, and the EXTENDS keyword to indicate that the new class inherits from an existing class.
The NEW keyword in Amiga E is used to create a new instance of an object.
AND and OR are logical operators. AND returns true if both operands are true, while OR returns true if at least one of the operands is true.
In Amiga E, a loop can be created using the FOR, WHILE, or UNTIL keywords. FOR is used for loops that execute a specific number of times, WHILE for loops that execute until a condition is false, and UNTIL for loops that execute until a condition is true.
The IF and ELSE keywords are used to create conditional statements. The code block following the IF keyword is executed if the condition is true, and the code block following the ELSE keyword is executed if the condition is false.
The candidate should have a deep understanding of Amiga E language, proficient problem-solving abilities, and excellent debugging skills. Red flags would be lack of experience with Amiga systems or inability to articulate complex coding processes clearly.
PROC main()
WriteF('Hello, World!')
ENDPROC
PROC main()
DEF a
a:=5
WriteF('Value of a is %d', a)
ENDPROC
PROC main()
DEF arr[5]:=[1,2,3,4,5]
FOR i:=0 TO 4 DO
WriteF('%d', arr[i])
ENDFOR
ENDPROC
PROC main()
DEF a:=NewProcess('PROC child() WriteF('Child process') ENDPROC')
WriteF('Parent process')
WaitProcess(a)
ENDPROC
OBJECT o
a
PROC init(n) a:=n ENDP
PROC print() WriteF('a is %d', a) ENDP
ENDOBJECT
PROC main()
DEF obj:=NEW o
obj\init(5)
obj\print()
ENDPROC
PROC main()
DEF a:=5, b:=10
Swap(a, b)
WriteF('a is %d, b is %d', a, b)
ENDPROC
PROC Swap(x, y)
DEF temp:=x
x:=y
y:=temp
ENDPROC
The final few interview questions for a Amiga E candidate should typically focus on a combination of technical skills, personal goals, growth potential, team dynamics, and company culture.
STATIC members belong to the class itself rather than instances of the class, and FINAL members cannot be overridden in a subclass.
Polymorphism in Amiga E is implemented using the OVERRIDE keyword to change the behavior of a method in a subclass.
The RESULT keyword is used to specify the value that a function returns.
The = operator is used for assignment, while the == operator is used for comparison.
PRIVATE and PUBLIC are access modifiers. PRIVATE members of a class are only accessible within that class, while PUBLIC members are accessible from outside the class.
Back-end App Developer
Front-end Web Developer
Full Stack Developer (Java)
Full Stack Developer (.Net)
Full Stack Developer (MEAN)
Full Stack Developer (MERN)
DevOps Engineer
Database Engineer (AzureSQL)
Database Engineer (Oracle)
Database Engineer (General)
Solution Architect (.NET)
Solution Architect (Java)
Solution Architect (Ruby)
Solution Architect (Python)
AI Engineer (Python)
Sr. AI Engineer (Python)
AI Strategist (Python)
Business Intelligence Engineer
Systems Analyst
Mainframe Developer (COBOL)
Mainframe Developer (General)